POJ-1035 Spell checker map标记

  题目链接:http://poj.org/problem?id=1035

  方法很多,hash标记判重也可以,然后就是分情况判断就可以了。。

 1 //STATUS:C++_AC_360MS_1132KB
 2 #include<stdio.h>
 3 #include<stdlib.h>
 4 #include<string.h>
 5 #include<math.h>
 6 #include<iostream>
 7 #include<string>
 8 #include<algorithm>
 9 #include<vector>
10 #include<queue>
11 #include<stack>
12 #include<map>
13 using namespace std;
14 #define LL __int64
15 #define pii pair<int,int>
16 #define Max(a,b) ((a)>(b)?(a):(b))
17 #define Min(a,b) ((a)<(b)?(a):(b))
18 #define mem(a,b) memset(a,b,sizeof(a))
19 #define lson l,mid,rt<<1
20 #define rson mid+1,r,rt<<1|1
21 #define put1(i,j,num) (li[i][0]|=(num<<(j<<1)))
22 #define get1(i,j) ((li[i][0]&(3<<(j<<1)))>>(j<<1))
23 #define put2(i,j,num) (li[i][1]|=(num<<j))
24 #define get2(i,j) ((li[i][1]&(1<<j))>>j)
25 const int N=10010,INF=0x3f3f3f3f,MOD=1999997;
26 const LL LLNF=0x3f3f3f3f3f3f3f3fLL;
27 
28 map<string,int> q;
29 char s[N][20];
30 int len[N];
31 int n;
32 
33 int judge1(char *a,char *b,int len)
34 {
35     int i,cou=0;
36     for(i=0;i<len;i++){
37         if(a[i]!=b[i])cou++;
38         if(cou==2)return 0;
39     }
40     return 1;
41 }
42 
43 int judge2(char *a,char *b,int len)
44 {
45     int i,j,cou=0;
46     for(i=j=0;i<len;i++,j++){
47         if(b[j]!=a[i])j--,cou++;
48         if(cou==2)return 0;
49     }
50     return 1;
51 }
52 
53 int main()
54 {
55  //   freopen("in.txt","r",stdin);
56     int i,j,lent;
57     char st[20];
58     n=0;
59     q.clear();
60     while(++n){
61         scanf("%s",s[n]);
62         if(s[n][0]=='#'){n--;break;}
63         q[s[n]]=1;
64         len[n]=strlen(s[n]);
65     }
66     while(scanf("%s",st)){
67         if(st[0]=='#')break;
68         if(q[st])printf("%s is correct\n",st);
69         else{
70             lent=strlen(st);
71             printf("%s:",st);
72             for(i=1;i<=n;i++){
73                 if(lent==len[i] && judge1(s[i],st,lent))
74                     printf(" %s",s[i]);
75                 else if(lent==len[i]+1 && judge2(st,s[i],lent))
76                     printf(" %s",s[i]);
77                 else if(lent+1==len[i] && judge2(s[i],st,len[i]))
78                     printf(" %s",s[i]);
79             }
80             putchar('\n');
81         }
82     }
83     return 0;
84 }

 

posted @ 2012-12-28 20:18  zhsl  阅读(281)  评论(0编辑  收藏  举报