【题解】「JOI 2015 Final」JOI 公园
Description
Solution
Code
#include <cstdio>
#include <algorithm>
#include <queue>
#define int long long
using namespace std;
const int MAXN = 1e5 + 10, MAXM = 4e5 + 5, INF = 1e18;
int n, m, C;
int head[MAXN], nxt[MAXM], ver[MAXM], edge[MAXM], tot;
int d[MAXN];
bool vis[MAXN];
void Dijkstra() {
priority_queue<pair<int, int> > q;
for (int i = 1; i <= n; i++)
d[i] = INF;
d[1] = 0;
q.push({0, 1});
while (q.size()) {
int u = q.top().second;
q.pop();
if (vis[u])
continue;
vis[u] = 1;
for (int i = head[u]; i; i = nxt[i]) {
int v = ver[i], w = edge[i];
if (d[v] > d[u] + w) {
d[v] = d[u] + w;
q.push({-d[v], v});
}
}
}
}
struct Node {
int w, d;
Node() {}
Node(int w, int d): w(w), d(d) {}
bool operator < (const Node o) const {
return d < o.d;
}
} t[MAXM];
int a[MAXM], b[MAXM], c[MAXM];
int sum[MAXN];
int ans;
void add(int x, int y, int w) {
nxt[++tot] = head[x], head[x] = tot, ver[tot] = y, edge[tot] = w;
}
signed main() {
scanf("%lld %lld %lld", &n, &m, &C);
for (int i = 1; i <= m; i++) {
scanf("%lld %lld %lld", &a[i], &b[i], &c[i]);
int u = a[i], v = b[i], w = c[i];
add(u, v, w), add(v, u, w);
ans += w;
}
Dijkstra();
for (int i = 1; i <= m; i++)
t[i] = Node(c[i], max(d[a[i]], d[b[i]]));
sort(t + 1, t + 1 + m);
for (int i = 1; i <= m; i++)
sum[i] = sum[i - 1] + t[i].w;
for (int i = 1; i <= n; i++) {
int l = 1, r = m, p;
while (l <= r) {
int mid = (l + r) >> 1;
if (t[mid].d <= d[i])
p = mid, l = mid + 1;
else
r = mid - 1;
}
ans = min(ans, C * d[i] + sum[m] - sum[p]);
}
printf("%lld", ans);
return 0;
}
本文来自博客园,作者:zhou_ziyi,转载请注明原文链接:https://www.cnblogs.com/zhouziyi/p/16558548.html
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