UOJ#191. 【集训队互测2016】Unknown 点分治 分治 整体二分 凸包 计算几何

原文链接https://www.cnblogs.com/zhouzhendong/p/UOJ191.html

题目传送门 - UOJ191

题意

自行移步集训队论文2016中罗哲正的论文。

题解

自行移步集训队论文2016中罗哲正的论文。

代码

所以说我就是来存代码的?

#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
LL read(){
	LL x=0,f=0;
	char ch=getchar();
	while (!isdigit(ch))
		f|=ch=='-',ch=getchar();
	while (isdigit(ch))
		x=(x<<1)+(x<<3)+(ch^48),ch=getchar();
	return f?-x:x;
}
const int N=300015,mod=998244353;
int Type,n,m,Q;
vector <int> e[N];
struct Gragh{
	static const int M=N;
	int cnt,y[M],nxt[M],fst[N];
	void clear(){
		cnt=1;
		memset(fst,0,sizeof fst);
	}
	void add(int a,int b){
		y[++cnt]=b,nxt[cnt]=fst[a],fst[a]=cnt;
	}
}qs;
struct Point{
	int x,y;
	Point(){}
	Point(int _x,int _y){
		x=_x,y=_y;
	}
	Point operator - (Point a){
		return Point(x-a.x,y-a.y);
	}
};
LL Cross(Point a,Point b){
	return (LL)a.x*b.y-(LL)b.x*a.y;
}
struct Query{
	Point a;//a for cross
	int f,x,tmp;
	LL ans;
}q[N];
int depth[N],fa[N];
Point P[N];
int new_node(int f,int d){
	n++;
	e[n].clear(),fa[n]=f,depth[n]=d;
	e[f].push_back(n);
	e[n].push_back(f);
	return n;
}
void build_tree(){
	static int st[N],d;
	st[d=Q=0]=n=1;
	e[n].clear(),fa[n]=0,depth[n]=d;
	while (m--){
		int opt=read(),L,R,x,y;
		if (opt==1){
			x=read(),y=read();
			d++;
			st[d]=new_node(st[d-1],d);
			P[n]=Point(x,y);
		}
		else if (opt==2)
			d--;
		else if (opt==3){
			L=read(),R=read(),x=read(),y=read();
			Q++;
			q[Q].a=Point(x,y);
			q[Q].f=st[L],q[Q].x=st[R];
			q[Q].ans=-5e18;
		}
	}
	qs.clear();
	for (int i=1;i<=Q;i++)
		qs.add(q[i].x,i);
}
int Size,RT;
int size[N],Max[N],vis[N];
void get_root(int x,int pre){
	size[x]=1,Max[x]=0;
	for (auto y : e[x])
		if (y!=pre&&!vis[y]){
			get_root(y,x);
			size[x]+=size[y];
			Max[x]=max(Max[x],size[y]);
		}
	Max[x]=max(Max[x],Size-size[x]);
	if (Max[x]<Max[RT])
		RT=x;
}
void get_size(int x,int pre){
	size[x]=1;
	for (auto y : e[x])
		if (y!=pre&&!vis[y])
			get_root(y,x),size[x]+=size[y];
}
Point A[N];
int qid[N],qtot;
void get_query(int x){
	for (int id=qs.fst[x];id;id=qs.nxt[id])
		if (depth[q[qs.y[id]].f]<=depth[RT])
			qid[++qtot]=qs.y[id];
	for (auto y : e[x])
		if (y!=fa[x]&&!vis[y])
			get_query(y);
}
bool cmp(int a,int b){
	return q[a].tmp<q[b].tmp;
}
bool cmp2(int a,int b){
	return Cross(q[a].a,q[b].a)<0;
}
Point tmp[N];
int Tmp[N];
void Unknown(int *qid,int qt,Point *P,int &pt){
	if (pt<=1)
		return (void)sort(qid+1,qid+qt+1,cmp2);
	int mid=pt>>1,ls=mid,rs=pt-mid,kk=0;
	while (kk<qt&&q[qid[kk+1]].tmp<mid)
		kk++;
	for (int i=kk+1;i<=qt;i++)
		q[qid[i]].tmp-=mid;
	Unknown(qid,kk,P,ls);
	Unknown(qid+kk,qt-kk,P+mid,rs);
	for (int i=kk+1,j=1;i<=qt;i++){
		while (j<ls&&Cross(P[j+1]-P[j],q[qid[i]].a)<0)
			j++;
		q[qid[i]].ans=max(q[qid[i]].ans,Cross(q[qid[i]].a,P[j]));
	}
	int tot=0,j=1;
	for (int i=1;i<=ls;){
		Point now=j<=rs&&P[j+mid].x<=P[i].x?P[mid+(j++)]:P[i++];
		while (tot>1&&Cross(tmp[tot]-tmp[tot-1],now-tmp[tot-1])>=0)
			tot--;
		tmp[++tot]=now;
	}
	for (;j<=rs;j++){
		Point now=P[j+mid];
		while (tot>1&&Cross(tmp[tot]-tmp[tot-1],now-tmp[tot-1])>=0)
			tot--;
		tmp[++tot]=now;
	}
	while (tot>1&&tmp[tot].x==tmp[tot-1].x&&tmp[tot].y<=tmp[tot-1].y)
		tot--;
	int h=1;
	while (h<tot&&tmp[h].x==tmp[h+1].x&&tmp[h].y<=tmp[h+1].y)
		h++;
	for (int i=h;i<=tot;i++)
		P[i-h+1]=tmp[i];
	pt=tot-h+1;
	tot=0,j=kk+1;
	for (int i=1;i<=kk;)
		if (j<=qt&&Cross(q[qid[j]].a,q[qid[i]].a)<0)
			Tmp[++tot]=qid[j++];
		else
			Tmp[++tot]=qid[i++];
	for (;j<=qt;j++)
		Tmp[++tot]=qid[j];
	for (int i=1;i<=qt;i++)
		qid[i]=Tmp[i];
}
void solve(int x){
	Max[RT=0]=N,get_root(x,0),x=RT,get_size(x,0);
	int t=0;
	for (int i=x;!vis[i];i=fa[i])
		A[++t]=P[i];
	vis[x]=1,RT=x,qtot=0,get_query(x);
	for (int i=1;i<=qtot;i++)
		q[qid[i]].tmp=min(t,depth[x]-depth[q[qid[i]].f]+1);
	sort(qid+1,qid+qtot+1,cmp);
	int k=1;
	while (k<=qtot&&q[qid[k]].tmp<t)
		k++;
	Unknown(qid,k-1,A,t);
	sort(qid+k,qid+qtot+1,cmp2);
	for (int i=k,j=1;i<=qtot;i++){
		while (j<t&&Cross(A[j+1]-A[j],q[qid[i]].a)<0)
			j++;
		q[qid[i]].ans=max(q[qid[i]].ans,Cross(q[qid[i]].a,A[j]));
	}
	for (auto y : e[x])
		if (!vis[y])
			Size=size[y],solve(y);
}
int main(){
	Type=read();
	while (m=read()){
		build_tree(),Size=n;
		memset(vis,0,sizeof vis);
		vis[0]=1,solve(1);
		int ans=0;
		for (int i=1;i<=Q;i++)
			ans^=(int)((q[i].ans%mod+mod)%mod);
		cout << ans << endl;
	}
	return 0;
}

  

posted @ 2018-12-15 17:23  zzd233  阅读(415)  评论(0编辑  收藏  举报