【2020090401】排名 rank over的用法

(1)rank over(order by 列名)------该函数只适用于oracle

例:

1 select sid, sname,  rank() over (order by score) as srank from sc;

(2)rank over(partition by 列名,order by 列名)

例:

1 select name, age, score, rank() over (partition by age order by score decs) as rank_num from student;

(按年龄分组,组内按分数降序排名)

 

注:dense_rank() 连续排名

  rank () 可不连续排名

1 -- 查询各科成绩前三名的记录
2 
3 SELECT cid, sid, score, srank FROM
4     (SELECT *, dense_rank() over (PARTITION by cid ORDER BY score DESC) AS srank
5     FROM sc)
6     AS t
7 WHERE t.srank<=3;

 

posted @ 2020-09-04 15:35  hi,好久不见  阅读(822)  评论(0编辑  收藏  举报