leetcode 题解: Length of Last Word
leetcode:
Given a string s consists of upper/lower-case alphabets and empty space characters ' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
说明:给定一个字符串,返回最后一个word的长度
1)字符串后面可以有空格,所以要去尾部空格
2)可能不含word,所以要判断字符串是否为空、或者是否只含有空格
1 class Solution { 2 public: 3 int lengthOfLastWord(const char *s) { 4 int len=strlen(s); 5 while(s[len-1]==' ') len--; //去尾部空格 6 if(len<0) return 0; //去空格后是否为空字符串 7 int i=0; 8 for(;s[len-1]&&s[len-1]!=' ';i++,len--); //求最后word长度 9 return i; 10 } 11 };