public class Solution {
public int myAtoi(String str) {
int index = 0, sign = 1, total = 0;
//1. 边界条件判断
if(str.length() == 0) return 0;
//2. 移除空格
while(str.charAt(index) == ' ' && index < str.length())
index ++;
//3. 处理符号位
if(str.charAt(index) == '+' || str.charAt(index) == '-'){
sign = str.charAt(index) == '+' ? 1 : -1;
index ++;
}
//4. 转变为int,并且避免溢出
while(index < str.length()){
int digit = str.charAt(index) - '0';
if(digit < 0 || digit > 9) break;
if(Integer.MAX_VALUE/10 < total || Integer.MAX_VALUE/10 == total && Integer.MAX_VALUE %10 < digit)
return sign == 1 ? Integer.MAX_VALUE : Integer.MIN_VALUE;
total = 10 * total + digit;
index ++;
}
return total * sign;
}
}