计算GPS两点间的距离[单位为:米]

/**
     * 计算GPS两点间的距离[单位为:米]
     * @param center GPS当前数据(LonLat对象表示,LonLat.lon表示经度，LonLat.lat表示纬度)
     * @param turnPoint 转向点经纬度对象
     * @return
     */
    private double gpsDistance( LonLat center, LonLat turnPoint )
    {
        double distance = 0;
        double lonRes = 102900, latRes = 110000;
        distance = Math.sqrt( Math.abs( center.lat - turnPoint.lat ) * latRes * Math.abs( center.lat - turnPoint.lat ) * latRes +
                Math.abs( center.lon - turnPoint.lon ) * lonRes * Math.abs( center.lon - turnPoint.lon ) * lonRes );
//        System.out.println( "两点间距离:" + distance );
        return distance;
    }

 

 

获得两点间的GPS距离

文章分类:移动开发

在android中可采用如下代码获取距离:

public double getDistance(double lat1, double lon1, double lat2, double lon2) {
    float[] results=new float[1];
    Location.distanceBetween(lat1, lon1, lat2, lon2, results);
    return results[0];
}

 

在其他设备若没有类似android的Location的distanceBetween方法开采用如下代码获取:

double distance(double lat1, double lon1, double lat2, double lon2) {
    double theta = lon1 - lon2;
    double dist = Math.sin(deg2rad(lat1)) * Math.sin(deg2rad(lat2))
                + Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2))
                * Math.cos(deg2rad(theta));
    dist = Math.acos(dist);
    dist = rad2deg(dist);
    double miles = dist * 60 * 1.1515;
    return miles;
}
//将角度转换为弧度
static double deg2rad(double degree) {
    return degree / 180 * Math.PI;
}
//将弧度转换为角度
static double rad2deg(double radian) {
    return radian * 180 / Math.PI;
}

 这个计算得出的结果是英里,如果要转换成公里,需要乘以1.609344,若是海里需要乘以0.8684

http://alex-yang-xiansoftware-com.javaeye.com/blog/649462

 

 

用于GPS换算世界上任意两点间距离C#实现

用于GPS换算世界上任意两点间距离

        /// 
        /// 计算地球上任意两点距离
        /// 
        /// 
        /// 
        /// 
        /// 
        /// 返回长度单位是米
        private static double Distance(double long1, double lat1, double long2, double lat2)
        {
            double a, b, R;
            R = 6378137; //地球半径
            lat1 = lat1 * Math.PI / 180.0;
            lat2 = lat2 * Math.PI / 180.0;
            a = lat1 - lat2;
            b = (long1 - long2) * Math.PI / 180.0;
            double d;
            double sa2, sb2;
            sa2 = Math.Sin(a / 2.0);
            sb2 = Math.Sin(b / 2.0);
            d = 2 * R * Math.Asin(Math.Sqrt(sa2 * sa2 + Math.Cos(lat1) * Math.Cos(lat2) * sb2 * sb2));
            return d;
        }

---------------------------------------------------------
专注移动开发
Android, Windows Mobile, iPhone, J2ME, BlackBerry, Symbian

http://www.blogjava.net/TiGERTiAN/archive/2010/05/01/319853.html

 

 

 

从google maps的脚本里扒了段代码，是用来计算两点间经纬度距离

private const double EARTH_RADIUS = 6378.137;
private static double rad(double d)
{
  return d * Math.PI / 180.0;
}

public static double GetDistance(double lat1, double lng1, double lat2, double lng2)
{
  double radLat1 = rad(lat1);
  double radLat2 = rad(lat2);
  double a = radLat1 - radLat2;
  double b = rad(lng1) - rad(lng2);
  double s = 2 * Math.Asin(Math.Sqrt(Math.Pow(Math.Sin(a/2),2) +  
  Math.Cos(radLat1)*Math.Cos(radLat2)*Math.Pow(Math.Sin(b/2),2)));
  s = s * EARTH_RADIUS;
  s = Math.Round(s * 10000) / 10000;
  return s;
}