数据结结构学习 ---赫夫曼树

------ 赫夫曼树和赫夫曼编码的存储表示------

 

typedef struct {
	unsigned int weight;
	unsigned int parent,lchild,rchild;
}HTNode,*HuffmanTree;
typedef char ** HuffmanCode;

void HuffmanCoding(HuffmanTree& HT,HuffmanCode & HC,int *w,int n)  {

	if (n < 1) return;\
	int	m = 2* n + 1;
	HT = (HuffmanTree) malloc (m+1)* sizeof(HTNode); //0 号单元未用
	for ( HuffmanTree p = HT; i=1; i<=n; ++i; ++p; ++w)  
		*p = {*w,0,0,0,0};
	for(; i<=m; ++i; ++p)
		*p = {0,0,0,0};

	for(i = n+1; i<=m; i++) {  //建立HuffmanTree

		Select(HT,i-1,s1,s2);
		HT[s1].parent = i; 
		HT[s2].parent = i; 
		HT[i].lchild = s1;
		HT[i].rchild = s2;
		HT[i].weight = HT[s1].weight + HT[s2].weight;
	}

	HC = (HuffmanCode)malloc((n+1)* sizeof(char*));
	cd = (char*) malloc(n* sizeof(char));
	cd [n-1] = "\0";
	for ( i=1; i<=n; i++) {
		int start = n-1;
		for ( c=i, f = HT[i].parent; f!=0; c=f; f = HT[f].parent )
			if( HT[f].lchild == c )  cd [--start] = "0";
			else cd [--start] = "1";
		HC[i] = (char*) malloc ( (n-start)* sizeof(char)); 
		strcyp(HC[i],&cd[start]);
	}
	free(cd);

}

 

------ 无栈非递归遍历赫夫曼树,求赫夫曼编码------

 

HC = (HuffmanCode) malloc ( (n+1) * sizeof(char*)); 
int p = m, cdlen = 0;

for ( int i=1; i<=m; ++i)  HT[i].weight = 0;

while(p) {

    if ( HT[p].weight == 0 ) {

        HT[p].weight = 1; 
        if ( HT[p].lchild != 0) {
            p = HT[p].lchild; 
            cd[cdlen++] = "0";
        }else if ( HT[p].lchild == 0) {

            HC[p] = (char*) malloc ((cdlen+1) * sizeof(char));
            cd[cdlen] = "\0"; 
            strcpy(HC[p],cd);
        }
    }else if ( HP[p].weight == 1) {

        HT[p].weight = 2;
        if ( HT[p].rchild != 0) {
            p = HT[p].rchild;
            cd [cdlen++] = "1";
        }else {
            HT[p].weight = 0; p = HT[p].parent; --cdlen;
        }
    }    
}

 

posted on 2012-11-30 07:33  莫水千流  阅读(312)  评论(0编辑  收藏  举报