2013年9月22日

摘要: 先附上源代码:#include void output1(){int i = 5;printf("%d,%d\n",i++,++i);}void output2(){int i = 5;printf("%d,%d\n",++i,i++);}void output3(){int i = 5;printf("%d\n",++i+i++);}void output4(){int i = 5;printf("%d\n",(i++)+(++i));}void output5(){int i = 5;printf(" 阅读全文
posted @ 2013-09-22 17:07 楠哥1991 阅读(613) 评论(0) 推荐(1) 编辑

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