ProjectEuler_P6
Question:
The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
C Code:
#include <stdio.h>
void main()
{
int i;
int sum1 = 0;
int sum2 = 0;
for(i = 1;i <= 100;i++)
{
sum1 += i*i;
sum2 += i;
}
printf("%d\n",sum2*sum2 - sum1);
}
Answer:
25164250