ProjectEuler_P1
Question:
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
C Code:
#include <stdio.h>
void main()
{
int i = 0;
int sum = 0;
while(i < 1000)
{
if(0 == i%3)
{
sum += i;
}
else if(0 == i%5)
{
sum += i;
}
i++;
}
printf("%d\n",sum);
}
Answer:
233168