1 #include<stdio.h>
2
3
4 /**
5 *判断闰年
6 */
7 int isR(int year){
8 if((year%4==0 || year%100==0)&&year%400!=0) {
9 return 1;
10 }
11 return 0;
12 }
13
14 /**
15 *如果参数合法，返回其至1990-01-01的时间长度
16 *否则返回0
17 */
18 int isLegal(int year, int m, int day) {
19 //对月份进行初始化
20 int isr = isR(year);
21 int month[13]= {0,31,29,31,30,31,30,31,31,30,31,30,31};
22 if(isr) {
23 month[2]=28;
24 }
25
26 //逐一校验
27 if(year < 1990) {
28 return 0;
29 }
30 if(m<=0 || m>12) {
31 return 0;
32 }
33 //日期合法性需要有月份来决定
34 switch(m) {
35 case 1: case 5: case 3: case 7: case 8: case 10: case 12:
36 if(day < 0 || day > 31){
37 return 0;
38 }
39 case 2:
40 if(isr == 1){
41 if(day > 28 || day < 0){
42 return 0;
43 }
44 }else {
45 if(day > 29 || day < 0){
46 return 0;
47 }
48 }
49 default:
50 if(day <0 || day > 30){
51 return 0;
52 }
53 }
54
55 int L=0;
56 //遍历年
57 for(int i=1990; i<year; i++){
58 if(isR(i)){
59 L+=366;
60 }else{
61 L+=365;
62 }
63 }
64 //遍历月
65 for(int i=1; i<m; i++){
66 L+=month[i];
67 }
68 //遍历日
69 L+=day;
70 return L;
71 }
72
73
74 int main() {
75 int year, month, day;
76 scanf("%4d-%2d-%2d", &year,&month,&day);
77 int L=isLegal(year, month, day);
78 if(L==0){
79 puts("Invalid input");
80 }else{
81 int n=L%5;
82 if(n>0 && n<=3){
83 puts("He is working");
84 }else{
85 puts("He is having a rest");
86 }
87 }
88 return 0;
89 }
