递归求1-100之和

递归求1-100之和

 

/*
    *求1-100之和
*/

function sum(num1, num2) {
    var num = num1 + num2;

    if (num2 + 1 > 100) {
        return num;
    } else {
        return sum(num, num2 + 1)
    }

}
var sum = sum(1, 2);   
console.log("sum ...",sum);

 

posted on 2021-04-09 18:00  zhishiyv  阅读(134)  评论(0编辑  收藏  举报

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