获取七天的日期

获取七天的日期

1. 需求分析

需要获取七天（包括当天）的数据进行分析

2. 导入依赖

<dependency>
	<groupId>cn.hutool</groupId>
	<artifactId>hutool-all</artifactId>
	<version>5.0.6</version>
</dependency>

3. 获取七天日期

	/**
     * 获取当前七天的时间
     * yyyy-MM-dd 00:00:00
     * 2022-08-01 00:00:00, 2022-08-02 00:00:00, 2022-08-03 00:00:00, 2022-08-04 00:00:00, 2022-08-05 00:00:00,
     * 2022-08-06 00:00:00, 2022-08-07 00:00:00, 2022-08-08 00:00:00
     *
     * @return
     */
    private List<DateTime> getDateTime() {
        List<DateTime> dateTimes = new ArrayList<>();
        String dateString = DateUtil.format(new Date(), "yyyy-MM-dd");
        DateTime dateTime = DateUtil.parseDate(dateString); // 2022-08-07 00:00:00
        DateTime dateTime1 = DateUtil.offsetDay(dateTime, 1); // 2022-08-08 00:00:00
        for (int i = 6; i > 0; i--) {
            dateTimes.add(DateUtil.offsetDay(dateTime, -i));
        }
        dateTimes.add(dateTime);
        dateTimes.add(dateTime1);
        return dateTimes;
    }

4. 数据处理

List<DateTime> dateTime = getDateTime();
for (int i = 0; i < dateTime.size() - 1; i++) {
	DateTime beginTime = dateTime.get(i);
	DateTime endTime = dateTime.get(i + 1);
	List<WorkOrder> workOrderList = workOrders.stream().filter(workOrder ->
                               DateUtil.parseDateTime(workOrder.getReleaseTime()).after(beginTime) &&
                               DateUtil.parseDateTime(workOrder.getReleaseTime()).before(endTime))
                               .collect(Collectors.toList());

}