摘要: select * from (select *,row_number() over(partition by PropertyRoofBeamID order by PropertyRoomID desc) as Sequencecount from PropertyRoom)t1 where Se 阅读全文
posted @ 2016-11-16 16:33 ☆♂安♀★ 阅读(1222) 评论(0) 推荐(0) 编辑