摘要: 题目传送门 Minimum Inversion Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 25116 Accepted Sub 阅读全文
posted @ 2018-11-05 22:25 better46 阅读(192) 评论(0) 推荐(0) 编辑
摘要: #define lson l , m , rt << 1 #define rson m + 1 , r , rt << 1 | 1 const int maxn = 55555; int sum[maxn<<2]; void PushUP(int rt) { sum[rt] = sum[rt<<1] 阅读全文
posted @ 2018-11-05 22:13 better46 阅读(214) 评论(0) 推荐(0) 编辑