摘要: m+n+p=0 m^2+n^2+p^2=4 m^4+n^4+p^4=? 解: m+n=-p (m+n)^2=p^2 (m^2+n^2)+2mn=p^2 (4-p^2)+2mn=p^2 2mn=2p^2-4 mn=p^2-2 (m^2+n^2)^2=(4-p^2)^2 m^4+2m^2n^2+n^4=(4-p^2)^2 m^4+2(p^2-2)^2+n^4=(4-p^2)^2 m^4+2(4... 阅读全文
posted @ 2019-02-14 11:08 琵琶真的行 阅读(262) 评论(0) 推荐(0) 编辑