金额转换

分享几种有关金额的js方法:

1.数字金额转大写

 1 function Chinese(num) {
 2         if (!/^\d*(\.\d*)?$/.test(num))throw(new Error(-1, "Number is wrong!"));
 3         var AA = new Array("零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖");
 4         var BB = new Array("", "拾", "佰", "仟", "萬", "億", "圆", "");
 5         var CC = new Array("角", "分", "厘");
 6         var a = ("" + num).replace(/(^0*)/g, "").split("."), k = 0, re = "";
 7         for (var i = a[0].length - 1; i >= 0; i--) {
 8             switch (k) {
 9                 case 0 :
10                     re = BB[7] + re;
11                     break;
12                 case 4 :
13                     if (!new RegExp("0{4}\\d{" + (a[0].length - i - 1) + "}$").test(a[0]))
14                         re = BB[4] + re;
15                     break;
16                 case 8 :
17                     re = BB[5] + re;
18                     BB[7] = BB[5];
19                     k = 0;
20                     break;
21             }
22             if (k % 4 == 2 && a[0].charAt(i) == "0" && a[0].charAt(i + 2) != "0") re = AA[0] + re;
23             if (a[0].charAt(i) != 0) re = AA[a[0].charAt(i)] + BB[k % 4] + re;
24             k++;
25         }
26         if (a[0].trim().charAt(0) == "") {       //  a = ["131321"]
27             re += AA[0];
28         }
29         if (a.length > 1) {
30             re += BB[6];
31             for (var i = 0; i < a[1].length; i++) {
32                 re += AA[a[1].charAt(i)] + CC[i];
33                 if (i == 2) break;
34             }
35             if (a[1].charAt(0) == "0" && a[1].charAt(1) == "0") {
36                 re += "元整";
37             }
38         } else {
39             re += "元整";
40         }
41         return re;
42     }
View Code

 

比如:

Chinese(123456789));// 壹億贰仟叁佰肆拾伍萬陆仟柒佰捌拾玖元整
View Code

2.数字转换为三位节 ,n---->小数点后保留的位数

 1  function fmoney(s, n) {
 2         n = n > 0 && n <= 20 ? n : 2;
 3         s = parseFloat((s + "").replace(/[^\d\.-]/g, "")).toFixed(n) + "";
 4         var l = s.split(".")[0].split("").reverse(),
 5                 r = s.split(".")[1];
 6         t = "";
 7         for (i = 0; i < l.length; i++) {
 8             t += l[i] + ((i + 1) % 3 == 0 && (i + 1) != l.length ? "," : "");
 9         }
10         return t.split("").reverse().join("") + "." + r;
11     }
View Code

比如:

1 fmoney(1234567,2));//12 1,234,567.00
2 fmoney(1234567,3));//12 1,234,567.000
View Code

 

posted @ 2016-04-25 21:24  郑叶叶  阅读(305)  评论(0编辑  收藏  举报