摘要: 计算同比 SELECT old.now_time, ROUND( ( new.count - old.count ) / old.count * 100, 2 ), new.count ncount, old.count ocount FROM ( SELECT sum( IF ( b.count 阅读全文
posted @ 2020-11-30 14:37 镇屌 阅读(239) 评论(0) 推荐(0) 编辑