151. 翻转字符串里的单词
方法一:使用双端队列
方法二:自定义api
对于java来说,字符串不可变,所以两个方法的时间,空间复杂度都相同
class Solution {
public String reverseWords(String s) {
int left = 0, right = s.length() - 1;
// 去掉字符串开头的空白字符
while (left <= right && s.charAt(left) == ' ') {
++left;
}
// 去掉字符串末尾的空白字符
while (left <= right && s.charAt(right) == ' ') {
--right;
}
Deque<String> d = new ArrayDeque<String>();
StringBuilder word = new StringBuilder();
while (left <= right) {
char c = s.charAt(left);
if ((word.length() != 0) && (c == ' ')) {
// 将单词 push 到队列的头部
d.offerFirst(word.toString());
word.setLength(0);
} else if (c != ' ') {
word.append(c);
}
++left;
}
d.offerFirst(word.toString());
return String.join(" ", d);
}
}
class Solution {
/**
* 不使用Java内置方法实现
* <p>
* 1.去除首尾以及中间多余空格
* 2.反转整个字符串
* 3.反转各个单词
*/
public String reverseWords(String s) {
// System.out.println("ReverseWords.reverseWords2() called with: s = [" + s + "]");
// 1.去除首尾以及中间多余空格
StringBuilder sb = removeSpace(s);
// 2.反转整个字符串
reverseString(sb, 0, sb.length() - 1);
// 3.反转各个单词
reverseEachWord(sb);
return sb.toString();
}
private StringBuilder removeSpace(String s) {
// System.out.println("ReverseWords.removeSpace() called with: s = [" + s + "]");
int start = 0;
int end = s.length() - 1;
while (s.charAt(start) == ' ') start++;
while (s.charAt(end) == ' ') end--;
StringBuilder sb = new StringBuilder();
while (start <= end) {
char c = s.charAt(start);
if (c != ' ' || sb.charAt(sb.length() - 1) != ' ') {
sb.append(c);
}
start++;
}
// System.out.println("ReverseWords.removeSpace returned: sb = [" + sb + "]");
return sb;
}
/**
* 反转字符串指定区间[start, end]的字符
*/
public void reverseString(StringBuilder sb, int start, int end) {
// System.out.println("ReverseWords.reverseString() called with: sb = [" + sb + "], start = [" + start + "], end = [" + end + "]");
while (start < end) {
char temp = sb.charAt(start);
sb.setCharAt(start, sb.charAt(end));
sb.setCharAt(end, temp);
start++;
end--;
}
// System.out.println("ReverseWords.reverseString returned: sb = [" + sb + "]");
}
private void reverseEachWord(StringBuilder sb) {
int start = 0;
int end = 1;
int n = sb.length();
while (start < n) {
while (end < n && sb.charAt(end) != ' ') {
end++;
}
reverseString(sb, start, end - 1);
start = end + 1;
end = start + 1;
}
}
}
作者:Zhbeii
出处:https://www.cnblogs.com/zhbeii/p/15812492.html
版权:本作品采用「署名-非商业性使用-相同方式共享 4.0 国际」许可协议进行许可。
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