调试示例

/*****x/2=1+1!/3+2!/3*5+3!/3*5*7+4!/3*5*7*9+...+i!/3*5*...(2*i+1)*****/
/***求x得值***/

#include<stdio.h>
double fact(double n);
double multi(double n);
int main(void)
{
    double i;
    double sum,item,eps;

    eps=1E-6;
    sum=1;
    item=1;

    for(i=1;item<=eps;i++){
        item=fact(i)/multi(2*i+1);
        sum=sum+item;
    }    
    printf("PI=%0.5lf\n",sum*2);

    return 0;
}
double fact(double n)
{
    double i;
    double res;

    res=1;
    for(i=1 ;i<=n;i++)
        res=res*i;

    return res;   
}

double multi(double n)
{
    double i;
    double res;

    res=1;
    for(i=3;i<=n;i=i+2)
        res=res*i;

    return res;    
}

 

/*******调试示例******/
/*输入三角形的三条边a，b，c，判断是否能构成一个三角形，若能，求其面积和周长*/
#include<stdio.h>
#include<math.h>
int main(void)
{
    double a,b,c;
    double area,perimeter,s;

    printf("Enter a,b,c:");
    scanf("%lf%lf%lf",&a,&b,&c);

    if(a+b>c&&a+c>b&&b+c>a){
        s=(a+b+c)/2;
    area=sqrt(s*(s-a)*(s-b)*(s-c));
    perimeter=a+b+c;

    printf("area=%.2lf;perimeter=%.2lf\n",area,perimeter);
    }
    else {
        printf("These sides do not correspond to a valid triangle\n");
    }

    return 0;
}}

 

/******调试示例******/

/*输入a，b，c，求一元二次方程ax^2+bx+c=0的根*/

#include<stdio.h>

#include<math.h>

int main(void)

{

         double a,b,c,d;

 

         printf("Enter a,b,c:");

         scanf("%lf%lf%lf",&a,&b,&c);

         d=b*b-4*a*c;         /*调试时设断点*/

         if(a==0)

                   if(b==0)

                            if(c==0)

                                     printf("参数都为0，方程无意义!\n");

                            else{

                                     printf("a和b都为0，c不为0，方成不成立\n");

}

                            else{

printf("x=%0.2f\n",-c/b);

}

else

if(d>=0)          /*调试时设断点*/

printf("x1=%0.2f\n",(-b+sqrt(d))/(2*a));

printf("x2=%0.2f\n",(-b-sqrt(d))/(2*a));

 

 

 if(d<0)

         printf("x1=%0.2f+%0.2fi\n",-b/(2*a),sqrt(-d)/(2*a));

         printf("x2=%0.2f-%0.2fi\n",-b/(2*a),sqrt(-d)/(2*a));

 

 

 

 

return 0;         /*调试时设断点*/

}