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Necklace of Beads Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1817 Necklace of Beads Submit Status 阅读全文
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Eddy's爱好 Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 2204 Eddy's爱好 Submit Status Practice HDU 2204 阅读全文
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转自:http://blog.csdn.net/dongfengkuayue/article/details/6461298 2. 用15乘以2(2为最终结果除以7的余数),用21乘以3(3为最终结果除以5的余数),同理,用70乘以2(2为最终结果除以3的余数),然后把三个乘积相加(15*2+21* 阅读全文