冒泡排序

假如有一个列表按照大小进行排序

#冒泡排序：按顺序排序

li = [33,2,10,1]

for j in range(1,len(li)):
    for i in range(len(li) - j):
        if li[i] > li[i + 1]:
            temp = li[i]
            li[i] = li[i + 1]
            li[i + 1] = temp
print(li)


#显示结果
#D:\Python35\python.exe D:/py_code/set/冒泡算法/冒泡算法.py
#[1, 2, 10, 33]

#Process finished with exit code 0

　

range函数用法

#!/usr/bin/env python
# -*- coding:utf-8 -*-


li = [33,2,10,1]
for j in range(5):
    print(j)
print("----------")

for i in range(1,5):
    print(i)


"""
显示结果
D:\Python35\python.exe D:/py_code/set/range函数.py
0
1
2
3
4
----------
1
2
3
4
"""