摘要: http://acm.hdu.edu.cn/showproblem.php?pid=1166可以直接暴力过:View Code 1 #include <stdio.h> 2 int main() 3 { 4 int a[50005],n,j,p,q,t,i,sum; 5 char ch[10]; 6 scanf("%d",&t); 7 for(j = 1;j <= t;j ++) 8 { 9 scanf("%d",&n);10 for(i = 1;i <= n;i ++)11 scanf("%d" 阅读全文
posted @ 2011-07-15 08:59 zhangteng 阅读(185) 评论(0) 推荐(0) 编辑