Hdu 1266 Reverse Number

Reverse Number

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 9927    Accepted Submission(s): 4410

Problem Description

Welcome to 2006'4 computer college programming contest!

Specially, I give my best regards to all freshmen! You are the future of HDU ACM! And now, I must tell you that ACM problems are always not so easy, but, except this one... Ha-Ha!

Give you an integer; your task is to output its reverse number. Here, reverse number is defined as follows:
1. The reverse number of a positive integer ending without 0 is general reverse, for example, reverse (12) = 21;
2. The reverse number of a negative integer is negative, for example, reverse (-12) = -21;
3. The reverse number of an integer ending with 0 is described as example, reverse (1200) = 2100.

 

 

Input

Input file contains multiple test cases. There is a positive integer n (n<100) in the first line, which means the number of test cases, and then n 32-bit integers follow.

 

 

Output

For each test case, you should output its reverse number, one case per line.

 

 

Sample Input

3

12

-12

1200

 

 

Sample Output

21

-21

2100

#include<stdio.h>  
#include<string.h>  
#define MAXN 10000  
char a[MAXN];  
int main()  
    {  
        int t, n, i, len;  
        int k;  
        scanf("%d", &t);  
        while( t-- )  
        {  
            scanf("%s", &a);  
            len = strlen(a);  
            for(k = len - 1; k >= 0; k--)  
            {  
                if(a[k] != '0')  
                    break;  
            }  
            if(a[0] == '-')  
            {  
                printf("-");  
                for(i = k; i >= 1; i--)  
                    printf("%c", a[i]);  
                for(i = k + 1; i < len; i++)  
                    printf("0");  
            }  
            else  
            {  
                for(i = k; i >= 0; i--)  
                    printf("%c", a[i]);  
                for(i = k + 1; i < len; i++)  
                    printf("0");  
            }  
            printf("\n");  
        }  
        return 0;  
}