一个List对象,想把特定的值排在最前面进行处理
今天遇到一个需求,要把list中的某些特定的值排在最前面处理,所以就要对list进行排序,搜索了一下进行总结
首先对List<String> 根据特定的值进行排序
List<String> list = Arrays.asList("apple", "banana", "cherry", "date", "sss", "fig"); List<String> specificValues = Arrays.asList("fig", "date"); // 指定的特定值 list.sort((a, b) -> { if (specificValues.contains(a)) { // a在指定值列表中,应排在前面 return -1; } else if (specificValues.contains(b)){ // b在指定值列表中,应排在前面 return 1; } else { // 其他情况保持不变 return 0; } }); System.out.println(list);
然后对一个List对象根据特定的值进行排序
首先去写一个简单的类
@Data public static class Student{ private String name; private String orderNo; private int classNum; public Student(String name, String orderNo, int i) { this.name = name; this.orderNo = orderNo; this.classNum = classNum; } } 然后main方法进行验证 List<Student> studentList = new ArrayList<Student>(); studentList.add(new Student("xiaopang","SN005",1)); studentList.add(new Student("xiaopang","SN002",1)); studentList.add(new Student("xiaopang","SN004",1)); studentList.add(new Student("xiaopang","SN001",1)); studentList.add(new Student("xiaopang","AN003",1)); studentList.add(new Student("xiaopang","AN001",1)); studentList.add(new Student("xiaopang","AN002",1)); // SN开头的再前面排列 studentList.sort((student1, student2) -> { if (student1.getOrderNo().contains("SN") && student2.getOrderNo().contains("SN")) { return student1.getOrderNo().compareTo(student2.getOrderNo()); } else if (student1.getOrderNo().contains("SN") && !student2.getOrderNo().contains("SN")) { return -1; } else if (!student1.getOrderNo().contains("SN") && student2.getOrderNo().contains("SN")) { return 1; } else { return student1.getOrderNo().compareTo(student2.getOrderNo()); } }); studentList.forEach(e->{ System.out.println(e.toString()); });
每天学习一点点,你就进步一点点。