LeetCode 190. Reverse Bits (算32次即可)

题目：

 

190. Reverse Bits

---

Reverse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).

Follow up:
If this function is called many times, how would you optimize it?

Related problem: Reverse Integer

Credits:
Special thanks to @ts for adding this problem and creating all test cases.

 

 

 

代码：

class Solution {
public:
    uint32_t reverseBits(uint32_t n) {
        uint32_t x = 0;
        int t = 32;
        while(t--){
            x = x*2+n%2;
            n /= 2;
        }
        return x;
    }
};