1083 List Grades （25 分）排序

1083 List Grades （25 分）

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output NONE instead.

Sample Input 1:

4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

Mike CS991301
Mary EE990830
Joe Math990112

Sample Input 2:

2
Jean AA980920 60
Ann CS01 80
90 95

Sample Output 2:

NONE

思路：
　　排序包括区间端点

#include<iostream>
#include<vector>
#include<algorithm>
#include<queue>
#include<string>
#include<map>
#include<set>
using namespace std;
struct Node
{
    string name;
    string id;
    int grade;
};

bool cmp(Node&A,Node&B)
{
    return A.grade>B.grade;
}


int main()
{
    int n;
    cin>>n;
    Node node[n];
    for(int i=0;i<n;i++)
        cin>>node[i].name>>node[i].id>>node[i].grade;
    int grade1,grade2;
    cin>>grade1>>grade2;
    sort(node,node+n,cmp);
    bool flag=false;
    for(int i=0;i<n;i++)
    {
        if(node[i].grade>=grade1&&node[i].grade<=grade2)
        {
            cout<<node[i].name<<" "<<node[i].id<<endl;
            flag=true;
        }


    }
    if(flag)
        cout<<"NONE";
    return 0;
}