codeforces 711B B. Chris and Magic Square(水题)
题目链接:
题意:
问在那个空位子填哪个数可以使行列对角线的和相等,就先找一行或者一列算出那个数,再验证是否可行就好;
AC代码:
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <bits/stdc++.h> #include <stack> #include <map> using namespace std; #define For(i,j,n) for(int i=j;i<=n;i++) #define mst(ss,b) memset(ss,b,sizeof(ss)); typedef long long LL; template<class T> void read(T&num) { char CH; bool F=false; for(CH=getchar();CH<'0'||CH>'9';F= CH=='-',CH=getchar()); for(num=0;CH>='0'&&CH<='9';num=num*10+CH-'0',CH=getchar()); F && (num=-num); } int stk[70], tp; template<class T> inline void print(T p) { if(!p) { puts("0"); return; } while(p) stk[++ tp] = p%10, p/=10; while(tp) putchar(stk[tp--] + '0'); putchar('\n'); } const LL mod=1e9+7; const double PI=acos(-1.0); const int inf=1e9; const int N=4e5+10; const int maxn=1e3+520; const double eps=1e-12; LL mp[505][505],l[505],r[505]; int main() { int n,x=0,y=0; read(n); For(i,1,n) { r[i]=0; For(j,1,n) { read(mp[i][j]); if(mp[i][j]==0) { x=i;y=j; } r[i]+=mp[i][j]; } } if(n==1) { cout<<"1\n"; return 0; } int num=0; for(int i=2;i<=n;i++) { if(r[i]!=r[i-1])num++; } if(num>2)cout<<"-1\n"; else { LL temp; if(x>1)temp=r[1]; else temp=r[2]; LL sum=temp; for(int i=1;i<=n;i++) { if(mp[x][i])temp-=mp[x][i]; } mp[x][y]=temp; if(temp<=0)cout<<"-1\n"; else { for(int i=1;i<=n;i++) { l[i]=0; for(int j=1;j<=n;j++) { l[i]+=mp[j][i]; } } for(int i=2;i<=n;i++) { if(l[i]!=sum) { cout<<"-1\n"; return 0; } } temp=0; for(int i=1;i<=n;i++) { temp+=mp[i][i]; } if(temp!=sum) { cout<<"-1\n"; return 0; } temp=0; for(int i=1;i<=n;i++) { temp+=mp[i][n-i+1]; } if(temp!=sum) { cout<<"-1\n"; return 0; } cout<<mp[x][y]<<endl; } } return 0; }