codeforces 709A A. Juicer(水题)

题目链接:

A. Juicer

题意:

给出n个橘子,汁漫出来了就倒出来,反正就是要求要倒几次;

思路:

 

AC代码:

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <bits/stdc++.h>
#include <stack>
#include <map>
 
using namespace std;
 
#define For(i,j,n) for(int i=j;i<=n;i++)
#define mst(ss,b) memset(ss,b,sizeof(ss));
 
typedef  long long LL;
 
template<class T> void read(T&num) {
    char CH; bool F=false;
    for(CH=getchar();CH<'0'||CH>'9';F= CH=='-',CH=getchar());
    for(num=0;CH>='0'&&CH<='9';num=num*10+CH-'0',CH=getchar());
    F && (num=-num);
}
int stk[70], tp;
template<class T> inline void print(T p) {
    if(!p) { puts("0"); return; }
    while(p) stk[++ tp] = p%10, p/=10;
    while(tp) putchar(stk[tp--] + '0');
    putchar('\n');
}
 
const LL mod=1e9+7;
const double PI=acos(-1.0);
const LL inf=1e18;
const int N=1e5+10;
const int maxn=1e3+20;
const double eps=1e-12;

int n,b,d;
int a[N];

int main()
{
    read(n);read(b);read(d);
    For(i,1,n)read(a[i]);
    LL ans=0,sum=0;
    For(i,1,n)
    {
        if(a[i]>b)continue;
        sum=sum+a[i];
        if(sum>d)ans++,sum=0;
    }
    cout<<ans<<endl;
    
    return 0;
}

  

posted @ 2016-08-25 11:00  LittlePointer  阅读(290)  评论(0编辑  收藏  举报