hdu-5655 CA Loves Stick(水题)
题目链接:
CA Loves Stick
Time Limit: 2000/1000 MS (Java/Others)
Memory Limit: 262144/262144 K (Java/Others)
Problem Description
CA loves to play with sticks.
One day he receives four pieces of sticks, he wants to know these sticks can spell a quadrilateral.
(What is quadrilateral? Click here: https://en.wikipedia.org/wiki/Quadrilateral)
One day he receives four pieces of sticks, he wants to know these sticks can spell a quadrilateral.
(What is quadrilateral? Click here: https://en.wikipedia.org/wiki/Quadrilateral)
Input
First line contains T denoting the number of testcases.
T testcases follow. Each testcase contains four integers a,b,c,d in a line, denoting the length of sticks.
1≤T≤1000, 0≤a,b,c,d≤263−1
T testcases follow. Each testcase contains four integers a,b,c,d in a line, denoting the length of sticks.
1≤T≤1000, 0≤a,b,c,d≤263−1
Output
For each testcase, if these sticks can spell a quadrilateral, output "Yes"; otherwise, output "No" (without the quotation marks).
Sample Input
2
1 1 1 1
1 1 9 2
Sample Output
Yes
No
题意:
给4条边,问能不能形成四边形;
思路:
三条边的和大于第四边就能形成,主要是和会爆long long 所以要做差;还要注意是0的情况;
AC代码:
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; long long a[5]; int main() { int t; scanf("%d",&t); while(t--) { for(int i=0;i<4;i++) { cin>>a[i]; } sort(a,a+4); if(a[0]==0)cout<<"No"<<endl; else { if(a[3]-a[0]-a[1]<a[2])cout<<"Yes"<<"\n"; else cout<<"No"<<"\n"; } } return 0; }