ural 1013. K-based Numbers. Version 3(动态规划)

1013. K-based Numbers. Version 3

Let’s consider K-based numbers, containing exactly N digits. We define a number to be valid if its K-based notation doesn’t contain two successive zeros. For example:
  • 1010230 is a valid 7-digit number;
  • 1000198 is not a valid number;
  • 0001235 is not a 7-digit number, it is a 4-digit number.
Given two numbers N and K, you are to calculate an amount of valid K based numbers, containing N digits.
You may assume that 2 ≤ K ≤ 10; N ≥ 2; N + K ≤ 1800.

Input

The numbers N and K in decimal notation separated by the line break.

Output

The result in decimal notation.

Sample

inputoutput
2
10
90

题意:

思路:和1009、1012一样;这三个题只是更改了数据范围;1012和本题用到了高精度运算;

 

 1 import java.util.Scanner;
 2 import java.util.regex.Pattern;
 3 import java.lang.Math;
 4 import java.math.BigInteger;
 5 
 6 
 7 
 8 public class t1 {
 9     public static void main(String[] args) {
10         Scanner ks=new Scanner(System.in);
11         BigInteger a,b,c,d,e;
12         a=new BigInteger("0");
13         b=new BigInteger("0");
14         c=new BigInteger("1");
15         d=new BigInteger("0");
16         e=new BigInteger("0");
17         int n,k;
18         n=ks.nextInt();
19         k=ks.nextInt();
20         int i;
21         for(i=1;i<k;i++)
22         {
23             d=d.add(c);//调出进制数减1;
24         }
25         b=b.add(d);
26         for(i=2;i<=n;i++)
27         {
28             e=b.multiply(c);//保存变量b的值;
29             b=b.add(a);//更新b的值;
30             b=b.multiply(d);//更新b的值
31             a=e.multiply(c);//跟新a的值;
32         }
33         b=a.add(b);
34         System.out.println(b.toString());
35     }
36 }
View Code

 

posted @ 2013-09-05 20:44  秋心无波  阅读(258)  评论(0编辑  收藏  举报