C# 判断字符串是否是int/double

 1 using System.Text.RegularExpressions;
 2 
 3 /// <summary>
 4 /// 判断字符串是否是int/double
 5 /// </summary>
 6 public static bool IsIntOrDouble(string strNumber)
 7 {
 8     Regex objNotNumberPattern = new Regex("[^0-9.-]");
 9     Regex objTwoDotPattern = new Regex("[0-9]*[.][0-9]*[.][0-9]*");
10     Regex objTwoMinusPattern = new Regex("[0-9]*[-][0-9]*[-][0-9]*");
11     const string strValidRealPattern = "^([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]+$";
12     const string strValidIntegerPattern = "^([-]|[0-9])[0-9]*$";
13     Regex objNumberPattern = new Regex("(" + strValidRealPattern + ")|(" + strValidIntegerPattern + ")");
14     return !objNotNumberPattern.IsMatch(strNumber) &&
15            !objTwoDotPattern.IsMatch(strNumber) &&
16            !objTwoMinusPattern.IsMatch(strNumber) &&
17            objNumberPattern.IsMatch(strNumber);
18 }

 

posted @ 2016-12-24 11:28  欣宇  阅读(2184)  评论(0编辑  收藏  举报