剑指offer-顺时针打印矩阵

题目描述

输入一个矩阵,按照从外向里以顺时针的顺序依次打印出每一个数字,例如,如果输入如下4 X 4矩阵: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 则依次打印出数字1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10.
 
首先判断需要走几圈,然后每圈依次按照向右向下向左向上的顺序遍历
 1 public ArrayList<Integer> printMatrix(int [][] matrix) {//my
 2        int rowlength = matrix.length;
 3         int collength = matrix[0].length;
 4         int count = ((rowlength<collength?rowlength:collength)-1)/2+1;
 5         ArrayList<Integer> result  = new ArrayList<Integer>();
 6         for (int i = 0; i < count; i++) {
 7             for (int j = i; j < collength-i; j++) {//向右
 8                 result.add(matrix[i][j]);
 9             }
10             for (int j = i+1; j < rowlength-i; j++) {//向下
11                 result.add(matrix[j][collength-i-1]);
12             }
13             for (int j = collength-i-2; j >= i&&(rowlength-i-1)>i; j--) {//向左 注意判断i的值
14                 result.add(matrix[rowlength-i-1][j]);
15             }
16             for (int j = rowlength-i-2; j > i &&(collength-i-1)>i; j--) {//向上 注意判断i的值
17                 result.add(matrix[j][i]);
18             }
19         }
20         return result;
21     }

 

posted @ 2019-04-11 16:25  月半榨菜  阅读(95)  评论(0编辑  收藏  举报