LeetCode-121. Best Time to Buy and Sell Stock

Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (i.e., buy one and sell one share of the stock), design an algorithm to find the maximum profit. Note that you cannot sell a stock before you buy one.

Example 1:

Input: [7,1,5,3,6,4]
Output: 5
Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5.
             Not 7-1 = 6, as selling price needs to be larger than buying price.

Example 2:

Input: [7,6,4,3,1]
Output: 0
Explanation: In this case, no transaction is done, i.e. max profit = 0.
public int maxProfit(int[] prices) {//my
        if(0>=prices.length){
            return 0;
        }
        int min = prices[0];
        int re = 0;
        for (int i = 1; i < prices.length; i++) {
            min = min<prices[i]?min:prices[i];
            re = re<(prices[i]-min)?(prices[i]-min):re;
        }
        return  re;
    }

  

相关题

买卖股票的最佳时间2 LeetCode122 https://www.cnblogs.com/zhacai/p/10596627.html

买卖股票的最佳时间3 LeetCode123 https://www.cnblogs.com/zhacai/p/10645571.html

买卖股票的最佳时间4 LeetCode188 https://www.cnblogs.com/zhacai/p/10645522.html

买卖股票的最佳时间冷冻期 LeetCode309 https://www.cnblogs.com/zhacai/p/10655970.html

买卖股票的最佳时间交易费 LeetCode714 https://www.cnblogs.com/zhacai/p/10659288.html

posted @ 2019-02-25 09:47  月半榨菜  阅读(142)  评论(0编辑  收藏  举报