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算法笔记--简单模拟

【PAT B1001】害死人不偿命的3n+1猜想

#include<stdio.h>
int main(){
    int step = 0;
    int n;
    printf("输入n的值:\t");
    scanf("%d", &n);

    while(n != 1){
        if(n % 2 == 0){
            n = n / 2;
            step++;
        }else{
            n = (3*n + 1) / 2;
            step++;
        }
    }

    printf("%d",step);

    return 0;

}

【PAT B1032】挖掘机技术哪家强

#include<stdio.h>

int main(){
    const int max = 100010;

    int num;
    int school[max] = {0};
    int sid, score;
    scanf("%d", &num);
    for(int i=0; i < num; i++){
        scanf("%d %d", &sid, &score);
        school[sid] = school[sid] + score;
    }

    int maxscore = -1, k = -1;

    for(int i=0; i < num; i++){
        if(school[i] > maxscore){
            maxscore = school[i];
            k = i;
        }
    }

    printf("%d %d", k, maxscore);

    return 0;
}

 

posted @ 2020-01-13 16:33  ZHGQCN  阅读(208)  评论(0编辑  收藏  举报