beanshell解析json(从简单到复杂)

使用beanshell 解析单层Json:

Json 数据如下:

{
"status":200,
"code": 0,
"message": "成功",
"data": {
"last": false,
"totalPages": 7,
"numberOfElements": 3,
"first": true,
"totalElements": 64,
"size": 10
}
}

则对于单层Json 则使用beanshell 如此解析:

思路:

1.接收返回值并定义为String 类型

2.将接收到的Sting 转换为JSONObject

3. 调用JSON对象中get()方法获得键值对中的值

 

1. //先引入Jar包
2. import org.json.*;
3. //获取请求返回值。只能获取到String
4. String response_data=prev.getResponseDataAsString();
5. //将string 类型返回值构造成Jsonobject 对象
6. JSONObject data_obj= new JSONObject(response_data);
7. //获取Json中 first的值
8. String apps_str= data_obj.get("data").get("first").toString();


使用beanshell 解析多层Json:

 

{
"status":200,
"code":0,
"message":"成功",
"data":{
"last":false,
"totalPages":7,
"numberOfElements":3,
"first":true,
"totalElements":64,
"size":10,
"content":[
{
"patrolJobId":"ff80808160058467016028b15b120cd0",
"pathName":"安管B班12月巡更",
"expectedStartTime":"2017-12-06T13:00:00+0800",
"expectedEndTime":"2017-12-06T19:00:00+0800",
"currentSystemTime":"2017-12-06T16:18:24+0800"
},
{
"patrolJobId":"ff80808160058467016028b15b130cd1",
"pathName":"安管B班12月巡更",
"expectedStartTime":"2017-12-06T19:00:00+0800",
"expectedEndTime":"2017-12-07T01:00:00+0800",
"currentSystemTime":"2017-12-06T16:18:25+0800"
}
]
},
"number":0
}


则对于多层Json 则使用beanshell 如此解析:

思路:

1.接收返回值并定义为String 类型

2.将接收到的Sting 转换为JSONObject

3.获取jsonarrary

4.调用Jsonarray对象中get()方法获得键值对中的值

 

import org.json.*;

//获取请求返回值。只能获取到String

String response_data=prev.getResponseDataAsString();

JSONObject data_obj= new JSONObject(response_data);

JSONArray apps_array= (JSONArray) ((JSONObject)data_obj.get("data")).get("content");

//获取第一串json 的patrolJobId

String patrolJobId= ((JSONObject)apps_array.get(0)).get("patrolJobId").toString();


使用beanshell 获取Json中所有该键(iBeaconUniqueCode)的值:

 

{
"status":200,
"code":0,
"message":"成功",
"data":{
"last":false,
"totalPages":7,
"numberOfElements":3,
"first":true,
"totalElements":64,
"size":10,
"content":[{
"patrolJobId":"ff80808160058467016028b15b120cd0",
"pathName":"安管B班12月巡更",
"expectedStartTime":"2017-12-06T13:00:00+0800",
"expectedEndTime":"2017-12-06T19:00:00+0800",
"currentSystemTime":"2017-12-06T16:18:24+0800",
"patrolUnitList":[
{
"signinTime":"2017-12-06T14:37:54+0800",
"unitName":"1座 1楼 3号铺",
"iBeaconUniqueCode": "GY-XC010103",
"signedIn":true
},
{
"unitName":"1座 1楼 8号铺",
"iBeaconUniqueCode": "GY-XC010108",
"signedIn":false
}
]
},
{
"patrolJobId":"ff80808160058467016028b15b130cd1",
"pathName":"安管B班12月巡更",
"expectedStartTime":"2017-12-06T19:00:00+0800",
"expectedEndTime":"2017-12-07T01:00:00+0800",
"currentSystemTime":"2017-12-06T16:18:25+0800",
"patrolUnitList":[
{
"unitName":"1座 1楼 3号铺",

"iBeaconUniqueCode": "GY-XC010103",

"signedIn":false
},
{
"unitName":"1座 1楼 8号铺",
"iBeaconUniqueCode": "GY-XC010108",
"signedIn":false
}
]
}
]
},
"number":0
}

 

思路:

new一个ArraryList,因为iBeaconUniqueCode存在于2层json 中,所以需要2层循环查找iBeaconUniqueCode,最后使用get()方法获取该值,并添加到ArraryList中

import org.json.*;

//获取请求返回值。只能获取到String

String response_data=prev.getResponseDataAsString();

JSONObject data_obj= new JSONObject(response_data);

JSONArrayapps_array= (JSONArray)((JSONObject)data_obj.get("data")).get("content");

ArrayList list =new ArrayList();
//外层循环获取JsonArrary的每一串Json
for(int j=0;j<apps_array.length();j++){
String apps_str1=apps_array.get(j).get("patrolUnitList").toString();
    JSONArray apps_array1= new JSONArray(apps_str1);
    for (int i=0;i<apps_array1.length();i++){
        //内层循环查找每个Json里的iBeaconUniqueCode值
        JSONObject app_obj= new JSONObject(apps_array1.get(i).toString());

        String iBeaconUniqueCode1= app_obj.get("iBeaconUniqueCode").toString();
        //将iBeaconUniqueCode值添加到ArrayList中
     list.add(iBeaconUniqueCode1);

}
}

String[] iBeaconUniqueCode= new String[list.size()];

for(int i=0;i<list.size();i++){

    iBeaconUniqueCode[i]=list.get(i);

}

vars.put("iBeaconUniqueCode", Arrays.toString(iBeaconUniqueCode));
---------------------
作者:城市的柏油路太硬
来源:CSDN
原文:https://blog.csdn.net/qq_34309753/article/details/78753307?utm_source=copy
版权声明:本文为博主原创文章,转载请附上博文链接!

posted @ 2018-10-13 14:04  小强找BUG  阅读(960)  评论(0编辑  收藏  举报