python 字典的减法
da = [
{"a": 231, "b": 456},
{"a": 423, "b": 980},
{"a": 846, "b": 1960},
{}
]
lst = []
for i in range(len(da) - 1): # 0 1
value1 = list(da[i].values())
value2 = list(da[i + 1].values())
if value1 and value2:
for j in range(len(value1)):
lst.append(value1[j] - value2[j])
print(lst)
##########结果
[-192, -524, -423, -980]
da = [
{"a": 231, "b": 456},
{"a": 423, "b": 980},
{"a": 846, "b": 1960},
{}
]
lst = []
for i in range(len(da) - 1): # 0 1
value1 = list(da[i].values())
value2 = list(da[i + 1].values())
if value1 and value2:
v_lst = []
for j in range(len(value1)):
v_lst.append(value1[j] - value2[j])
lst.append(v_lst)
print(lst)
#############结果
[[-192, -524], [-423, -980]]
lst = []
for i in range(len(da) - 1): # 0 1
value1 = list(da[i].values())
value2 = list(da[i + 1].values())
v_lst = []
if not value1:
lst.append(v_lst)
elif not value2:
lst.append(v_lst)
elif value1 and value2:
for j in range(len(value1)):
v_lst.append(value1[j] - value2[j])
lst.append(v_lst)
print(lst)
################结果
[[], [-192, -524], [], [], []]
这种稍微麻烦一点 需要给每个字典的外层在加一层列表好用索引来
lis = [
[
{
'应收账款': 2154.00,
'存货': 4308.00,
}
],
[
{
'应收账款': 308.00,
'存货':4308.00,
}
],
]
this_month = []
for m in range(1):
for base_dict, sub_dict in zip(lis[m], lis[m + 1]):
this_month.append({k: v - sub_dict.get(k, 0) for k, v in base_dict.items()})
print(this_month)
那个满足就用那个吧,能实现功能就行