处理回车事件是否有既兼容ie又兼容火狐的方法
document.onkeypress = function (e) {
var code;
if (!e) {
var e = window.event;
}
if (e.keyCode) {
code = e.keyCode;
}
else if (e.which) {
code = e.which;
}
if (code == 13) {
document.getElementById("searchButton").click();
return false;
}
}