Java多线程10:join()方法
一、前言
通过一个简单的例子引入join()方法
public class Thread01 extends Thread{ @Override public void run() { for(int i = 0; i < 5; i++) { System.out.println(Thread.currentThread().getName() + "=" + i); } } }
main线程中起两个线程
public class Test { public static void main(String[] args) throws InterruptedException { Thread01 thread01 = new Thread01(); Thread01 thread02 = new Thread01(); thread01.start(); thread02.start(); } }
结果:
Thread-1=0 Thread-0=0 Thread-0=1 Thread-0=2 Thread-1=1 Thread-0=3 Thread-1=2 Thread-0=4 Thread-1=3 Thread-1=4
说明:可以看到,thread01和thread02并发执行,没有先后顺序,现在在thread01.start()之后加入join()方法
public class Test { public static void main(String[] args) throws InterruptedException { Thread01 thread01 = new Thread01(); Thread01 thread02 = new Thread01(); thread01.start(); thread01.join(); System.out.println("main thread after join"); thread02.start(); } }
其他不变,看一下结果:
Thread-0=0 Thread-0=1 Thread-0=2 Thread-0=3 Thread-0=4 main thread after join Thread-1=0 Thread-1=1 Thread-1=2 Thread-1=3 Thread-1=4
说明:可以看到,thread01在调用join()后,会优先执行,等它执行完了,才会执行thread02。在分析main线程中的执行过程之前,先看一下join()方法的源码。
二、join()/join(long millis)
/** * Waits for this thread to die. * * <p> An invocation of this method behaves in exactly the same * way as the invocation * * <blockquote> * {@linkplain #join(long) join}{@code (0)} * </blockquote> * * @throws InterruptedException * if any thread has interrupted the current thread. The * <i>interrupted status</i> of the current thread is * cleared when this exception is thrown. */ public final void join() throws InterruptedException { join(0); }
join()方法调用了join(long millis)方法,注意下面这个注释:意思是最多等待几ms线程(比如thread01)结束,但若是在指定的时间内没有结束,那么调用该方法的线程(calling thread 比如main)会被唤醒,和thread01并发执行。
Waits at most {@code millis} milliseconds for this thread to die
/** * Waits at most {@code millis} milliseconds for this thread to * die. A timeout of {@code 0} means to wait forever. * * <p> This implementation uses a loop of {@code this.wait} calls * conditioned on {@code this.isAlive}. As a thread terminates the * {@code this.notifyAll} method is invoked. It is recommended that * applications not use {@code wait}, {@code notify}, or * {@code notifyAll} on {@code Thread} instances. * * @param millis * the time to wait in milliseconds * * @throws IllegalArgumentException * if the value of {@code millis} is negative * * @throws InterruptedException * if any thread has interrupted the current thread. The * <i>interrupted status</i> of the current thread is * cleared when this exception is thrown. */ public final synchronized void join(long millis) throws InterruptedException { long base = System.currentTimeMillis(); long now = 0; if (millis < 0) { throw new IllegalArgumentException("timeout value is negative"); } if (millis == 0) { while (isAlive()) { wait(0); } } else { while (isAlive()) { long delay = millis - now; if (delay <= 0) { break; } wait(delay); now = System.currentTimeMillis() - base; } } }
join(long millis)是同步方法,该方法是通过循环判断线程的isAlive的值(调用join方法的线程)来调用wait方法。当有线程执行完了,notifyAll方法会被调用,使其他处于等待的线程开始执行。
分析一下main方法中的执行过程。在main线程中,首先thread01依次调用start()-->join()-->join(0)方法,因为join(long millis)是同步方法,main线程会去获取与thread01对象关联的monitor的所有权(The thread that executes monitorenter attempts to gain ownership of the monitor associated with objectref),thread01对象关联的monitor还没有被别的线程所有,所以main线程进入该同步方法,传入的参数millis为0,接着判断thread01线程isAlive(Tests if this thread is alive. A thread is alive if it has been started and has not yet died),为true,调用wait()方法,main线程处于等待状态,而thread01线程继续执行,当thread01线程执行完毕,join(long millis)方法结束,notifyAll()方法会被调用,main线程被唤醒,继续执行,打印出"main thread after join"语句,执行thread02线程。