使用C#调用Python脚本,带参数列表 z

static void Main(string[] args)
        {
            string[] strArr;//参数列表
         string sArguments = @"Pythons.py";//这里是python的文件名字
         RunPythonScript(sArguments, "-u", strArr);
    
            }

public static void RunPythonScript(string sArgName, string args = "",params string[] teps)
        {
            Process p = new Process();
            string path = System.AppDomain.CurrentDomain.SetupInformation.ApplicationBase + sArgName;// 获得python文件的绝对路径     
            p.StartInfo.FileName = @"python";
            string sArguments = path;
            if (tep.Length > 0)
            {
                foreach (string sigstr in teps)
                {
                    sArguments += " " + sigstr;//传递参数
                }
            }
            if (args.Length > 0)
            {

                sArguments += " " + args;

            }

            p.StartInfo.Arguments = sArguments;

            p.StartInfo.UseShellExecute = false;

            p.StartInfo.RedirectStandardOutput = true;

            p.StartInfo.RedirectStandardInput = true;

            p.StartInfo.RedirectStandardError = true;

            p.StartInfo.CreateNoWindow = true;

            p.Start();
            p.BeginOutputReadLine();
            p.OutputDataReceived += new DataReceivedEventHandler(p_OutputDataReceived);
            Console.ReadLine();
            p.WaitForExit();
        }
        //输出打印的信息
        static void p_OutputDataReceived(object sender, DataReceivedEventArgs e)
        {
            if (!string.IsNullOrEmpty(e.Data))
            {
                 AppendText(e.Data + Environment.NewLine);
            }
        }
        public delegate void AppendTextCallback(string text);
        public static void AppendText(string text)
        {
            Console.WriteLine(text);
           
        }

传递参数时,每个参数中间要有一个空格

 

Python接收参数的方法:
从1开始接收参数

args1= sys.argv[1]

args2=sys.argv[2]

args2=sys.argv[3]

posted on 2014-03-29 12:22  武胜-阿伟  阅读(8361)  评论(0编辑  收藏  举报