摘要：
One day Vasya was sitting on a not so interesting Maths lesson and making an origami from a rectangularamm × bmm sheet of paper (a > b). Usually the f... 阅读全文
摘要：
Description众所周知，我是好人！所以不会出太难的题，题意很简单 给你两个数n和m，问你有多少对正整数对最大公约数是n，最小公倍数是m最后友情提供解题代码（我真是太好人了）void solve(){ long long n, m; scanf("%lld%lld", &n, &m); int... 阅读全文