模板——矩阵快速幂
/************************************************ Author :powatr Created Time :2015-8-5 21:06:30 File Name :b.cpp ************************************************/ #include <cstdio> #include <algorithm> #include <iostream> #include <sstream> #include <cstring> #include <cmath> #include <string> #include <vector> #include <queue> #include <deque> #include <stack> #include <list> #include <map> #include <set> #include <bitset> #include <cstdlib> #include <ctime> using namespace std; #define lson l, mid, rt << 1 #define rson mid + 1, r, rt << 1 | 1 typedef long long ll; const int MAX = 50;//矩阵大小 int n; const int INF = 0x3f3f3f3f; const int mod = 1e9 + 7; struct Matrix { int a[MAX][MAX]; void inti() { memset(a, 0, sizeof(a)); for(int i = 0 ; i < n; i++) a[i][i] = 1; } }matrix; Matrix mul(Matrix a, Matrix b)//矩阵乘法 { Matrix ans; for(int i = 0 ; i < n; i++) for(int j = 0 ; j <n ;j++){ ans.a[i][j] = 0; for(int k = 0; k < n; k++){
if(a.a[i][k] == 0 || b.a[k][j] == 0) continue; ans.a[i][j] += a.a[i][k] * b.a[k][j]; ans.a[i][j] %= mod;
} } return ans; } Matrix add(Matrix a, Matrix b) //矩阵加法 { int i, j, k; Matrix ans; for(int i = 0 ; i < n; i++) for(int j = 0 ; j < n; j++){ ans.a[i][j] = a.a[i][j] + b.a[i][j]; ans.a[i][j] %= mod; } return ans; } Matrix pow(Matrix a, int n) // 矩阵快速幂 { Matrix ans; ans.inti(); while(n){ if(n&1) ans = mul(ans, a); n>>= 1; a = mul(a, a); } return ans; } Matrix sum(Matrix a, int n)//矩阵幂和 { int m; Matrix ans, pre; if(n == 1) return a; m = n >> 1; pre = sum(a, m); ans = add(pre, mul(pre, pow(a, m))); if(n&1) ans = add(ans, pow(a, n)); return ans; } void output(Matrix a) //输出 { for(int i = 0 ; i < n; i++) for(int j = 0 ; j < n ; j++) printf("%d%c",a.a[i][j], j == n -1 ? '\n' : ' '); } int main() { Matrix ans; scanf("%d", &n); for(int i = 0 ; i < n; i++) for(int j = 0; j < n; j++){ scanf("%d%d", &matrix.a[i][j]); matrix.a[i][j] %= mod; } return 0; }