unsigned int与int相加的问题-----C/C++小知识 区别

http://blog.csdn.net/thefutureisour/article/details/8147277

 

#include "stdafx.h"

int _tmain(int argc, _TCHAR* argv[])
{
unsigned int a=32;

int b=-6;

unsigned int c=a+b;        //把b转化为unsigned int   0xfffffffa +   0x00000020 ----->26(十进制)    //-6补码被当成一个无符号数

 

printf("%u",c);


}

 

c      0x0000001a         unsigned int

b      0xfffffffa               int

a      0x00000020        unsigned int

 

posted @ 2017-06-27 20:55  zengkefu  阅读(2117)  评论(0编辑  收藏  举报