6-5 链式表操作集

6-5 链式表操作集(20 分)

本题要求实现链式表的操作集。

函数接口定义:

Position Find( List L, ElementType X );
List Insert( List L, ElementType X, Position P );
List Delete( List L, Position P );

其中List结构定义如下:

typedef struct LNode *PtrToLNode;
struct LNode {
    ElementType Data;
    PtrToLNode Next;
};
typedef PtrToLNode Position;
typedef PtrToLNode List;

各个操作函数的定义为:

Position Find( List L, ElementType X ):返回线性表中首次出现X的位置。若找不到则返回ERROR;

List Insert( List L, ElementType X, Position P ):将X插入在位置P指向的结点之前,返回链表的表头。如果参数P指向非法位置,则打印“Wrong Position for Insertion”,返回ERROR;

List Delete( List L, Position P ):将位置P的元素删除并返回链表的表头。若参数P指向非法位置,则打印“Wrong Position for Deletion”并返回ERROR。

裁判测试程序样例:

#include <stdio.h>
#include <stdlib.h>

#define ERROR NULL
typedef int ElementType;
typedef struct LNode *PtrToLNode;
struct LNode {
    ElementType Data;
    PtrToLNode Next;
};
typedef PtrToLNode Position;
typedef PtrToLNode List;

Position Find( List L, ElementType X );
List Insert( List L, ElementType X, Position P );
List Delete( List L, Position P );

int main()
{
    List L;
    ElementType X;
    Position P, tmp;
    int N;

    L = NULL;
    scanf("%d", &N);
    while ( N-- ) {
        scanf("%d", &X);
        L = Insert(L, X, L);
        if ( L==ERROR ) printf("Wrong Answer\n");
    }
    scanf("%d", &N);
    while ( N-- ) {
        scanf("%d", &X);
        P = Find(L, X);
        if ( P == ERROR )
            printf("Finding Error: %d is not in.\n", X);
        else {
            L = Delete(L, P);
            printf("%d is found and deleted.\n", X);
            if ( L==ERROR )
                printf("Wrong Answer or Empty List.\n");
        }
    }
    L = Insert(L, X, NULL);
    if ( L==ERROR ) printf("Wrong Answer\n");
    else
        printf("%d is inserted as the last element.\n", X);
    P = (Position)malloc(sizeof(struct LNode));
    tmp = Insert(L, X, P);
    if ( tmp!=ERROR ) printf("Wrong Answer\n");
    tmp = Delete(L, P);
    if ( tmp!=ERROR ) printf("Wrong Answer\n");
    for ( P=L; P; P = P->Next ) printf("%d ", P->Data);
    return 0;
}

/* 你的代码将被嵌在这里 */

输入样例:

6
12 2 4 87 10 2
4
2 12 87 5

输出样例:

2 is found and deleted.
12 is found and deleted.
87 is found and deleted.
Finding Error: 5 is not in.
5 is inserted as the last element.
Wrong Position for Insertion
Wrong Position for Deletion
10 4 2 5
思路:调试了好一小会😤

Position Find(List L, ElementType X)
{
    List list = L;
    while (list){
        if (list->Data == X)
            return list;
        list = list->Next;
    }
    return ERROR;
}
List Insert(List L, ElementType X, Position P)
{

    
    List temp = (List)malloc(sizeof(struct LNode));
    temp->Data = X;
    temp->Next = NULL;

    if (L == P){
        temp->Next = L;
        return temp;
    }

    List list = L;
    while (list->Next!= P){

        if (list->Next == NULL){
            printf("Wrong Position for Insertion\n");
            return ERROR;
        }
        list = list->Next;
    }
    temp->Next = list->Next;
    list->Next = temp;
    return L;
        
}
List Delete(List L, Position P)
{
    if (P == NULL){
        printf("Wrong Position for Deletion\n");
        return ERROR;
    }
    List list = L;
    if (list == P){
        list = list->Next;
        return list;        //不是等价于return L ;吗??????
    }
    while (list->Next != P){
        if (list->Next == NULL){
            printf("Wrong Position for Deletion\n");
            return ERROR;
        }
        list = list->Next;
    }
    list->Next = list->Next->Next;
    return L;
}

 

 

 

posted @ 2018-01-28 21:30  我只有一件白T恤  阅读(530)  评论(0编辑  收藏  举报