localtime 和 localtime_r 的区别
转自:http://blog.csdn.net/maocl1983/article/details/6221810 #include <cstdlib> #include <iostream> #include <time.h> #include <stdio.h> using namespace std; int main(int argc, char *argv[]) { time_t tNow =time(NULL); time_t tEnd = tNow + 1800; //注意下面两行的区别 struct tm* ptm = localtime(&tNow); struct tm* ptmEnd = localtime(&tEnd); char szTmp[50] = {0}; strftime(szTmp,50,"%H:%M:%S",ptm); char szEnd[50] = {0}; strftime(szEnd,50,"%H:%M:%S",ptmEnd); printf("%s /n",szTmp); printf("%s /n",szEnd); system("PAUSE"); return EXIT_SUCCESS; } 最后出来的结果是:21:18:39 21:18:39 和最初想法不一致。查阅localtime的文档,发现这段话:This structure is statically allocated and shared by the functions gmtime and localtime. Each time either one of these functions is called the content of this structure is overwritten.也就是说每次只能同时使用localtime()函数一次,要不就会被重写!The localtime() function need not be reentrant. A function that is not required to be reentrant is not required to be thread-safe.因此localtime()不是可重入的。同时libc里提供了一个可重入版的函数localtime_r();Unlike localtime(), the reentrant version is not required to set tzname。 修改程序: #include <cstdlib> #include <iostream> #include <time.h> #include <stdio.h> using namespace std; int main(int argc, char *argv[]) { time_t tNow =time(NULL); time_t tEnd = tNow + 1800; //在这里修改程序 //struct tm* ptm = localtime(&tNow); //struct tm* ptmEnd = localtime(&tEnd); struct tm ptm = { 0 }; struct tm ptmEnd = { 0 }; localtime_r(&tNow, &ptm); localtime_r(&tEnd, &ptmEnd); char szTmp[50] = {0}; strftime(szTmp,50,"%H:%M:%S",&ptm); char szEnd[50] = {0}; strftime(szEnd,50,"%H:%M:%S",&ptmEnd); printf("%s /n",szTmp); printf("%s /n",szEnd); system("PAUSE"); return EXIT_SUCCESS; } 最后出来的结果是:10:29:06 10:59:06
posted on 2015-11-24 11:34 zyz913614263 阅读(1362) 评论(0) 编辑 收藏 举报