php的__clone()方法对一个对象实例进行的浅复制,对象内的基本数值类型进行的是传值复制,而对象内的对象型成员变量,如果不重写__clone方法,显式的clone这个对象成员变量的话,这个成员变量就是传引用复制,而不是生成一个新的对象.如第28行注释所说

 1  <?php
 2     class Account {
 3         public $balance;
 4         
 5         public function __construct($balance) {
 6             $this->balance = $balance;
 7         }
 8     }
 9  
10     class Person {
11         private $id;
12         private $name;
13         private $age;
14         public $account;
15         
16         public function __construct($name, $age, Account $account) {
17             $this->name = $name;
18             $this->age = $age;
19             $this->account = $account;
20         }
21         
22         public function setId($id) {
23             $this->id = $id;
24         }
25         
26         public function __clone() {    #复制方法,可在里面定义再clone是进行的操作
27             $this->id = 0;
28             $this->account = clone $this->account;    #不加这一句,account在clone是会只被复制引用,其中一个account的balance被修改另一个也同样会被修改
29         }
30     }
31     
32     $person = new Person("peter", 15, new Account(1000));
33     $person->setId(1);
34     $person2 = clone $person;
35     
36     $person2->account->balance = 250;
37     
38     var_dump($person, $person2);
39     
40  ?>

输出:

object(Person)#1 (4) { ["id":"Person":private]=> int(1) ["name":"Person":private]=> string(5) "peter" ["age":"Person":private]=> int(15) ["account"]=> object(Account)#2 (1) { ["balance"]=> int(1000) } } object(Person)#3 (4) { ["id":"Person":private]=> int(0) ["name":"Person":private]=> string(5) "peter" ["age":"Person":private]=> int(15) ["account"]=> object(Account)#4 (1) { ["balance"]=> int(250) } }

posted on 2012-05-31 02:55  ZimZz  阅读(14008)  评论(4编辑  收藏  举报