dict 使用多个key组成的path赋值
2020-01-08 14:23 ZealouSnesS 阅读(447) 评论(0) 编辑 收藏 举报def nested_set(dic, keys, value): for key in keys[:-1]: dic = dic.setdefault(key, {}) dic[keys[-1]] = value
def nested_set(dic, keys, value): for key in keys[:-1]: dic = dic.setdefault(key, {}) dic[keys[-1]] = value
