摘要: 传送门 A - ∴ (Therefore) #include <bits/stdc++.h> #define ll long long using namespace std; int main() { int n; scanf("%d", &n), n %= 10; if(n == 2 || n 阅读全文
posted @ 2020-05-18 13:09 zdragon 阅读(428) 评论(0) 推荐(2) 编辑