用shell编写一个三角形图案

第一种方法

#!/bin/bash

read -p "请输入层数: " n

for (( i=1; i<=$n;i++ ))
do
   for (( j=n; j>=i;j-- ))
do
        echo -n " "
done
for (( j=1;j<=i;j++ ))
do
    echo -n " *"
  done
  echo
done

另外一种方案:三角形简单

#!/bin/bash


for i in {1..9}
do
for a in {1..9}
do
if [ $a -ge $i ]
then
echo -n " "
fi
done
for b in {1..9}
do
if [ $b -le $i ]
then
echo -n "*"
fi
       done
        for h in {1..9}
        do
                if [ $h -lt $i ]
        then
        echo -n "*"
        fi
        done
        echo
done

posted @ 2019-05-19 12:28  #赵程#  阅读(849)  评论(0编辑  收藏  举报